Question

Area of a trapezium is 320 cm² and 16
cm and 48 cm are lengths of two
parallel sides, then the distance
between the two parallel sides is
(in cm)​

Answer 1

Answer:

Step-by-step explanation:

To attempt this question, we need to know the formula :-

$\sf{Area \ of \ Trapezium = \dfrac{1}{2} \times (Sum \ of \ Parallel \ sides) \times height}$

Now, we are given the following information :-

• Sides are 16 cm and 48 cm
• The area of the trapezium is 320 cm^2

Now, we can place it in the above formula :-

$\sf{Area \ of \ Trapezium = \dfrac{1}{2} \times (Sum \ of \ Parallel \ sides) \times height}$

$\sf{320 = \dfrac{1}{2} \times (16 + 48) \times height}$

$\sf{320 = \dfrac{1}{2} \times (64) \times height}$

$\sf{320 = 32 \times height}$

$\sf{\dfrac{320}{32} =  height}$

$\sf{10 \ cm =  height}$

So, the distance between the parallel side is 10 cm. Hence, the required answer.

Answer 2

Given :-

Area of a trapezium is 320 cm² and 16  cm and 48 cm are lengths of two  parallel sides

To Find :-

Distance between them

Solution :-

Let the height be h

Area = 1/2 × (a + b) × h

320 = 1/2 × (48 + 16) × h

320 × 2 = 64 × h

640 = 64h

640/64 = h

10 = h

Hence

Distance between them is 10 cm.