Question

Area of a trapezium is 320 cm² and 16
cm and 48 cm are lengths of two
parallel sides, then the distance
between the two parallel sides is
(in cm)​

Answer 1

Answer:

10cm

Step-by-step explanation:

area of trapezium = $\frac{1}{2} * height*(a+b)$

height = x

$320cm^{2} = \frac{1}{2} * (16+48)*x\\\\320 = \frac{1}{2}*64*x\\\\320=32x\\\\x=\frac{320}{32}\\\\x= 10$

Answer 2

Answer:

10cm

Step-by-step explanation:

area of trapezium = \frac{1}{2} * height*(a+b)

2

1

∗height∗(a+b)

height = x

\begin{gathered}320cm^{2} = \frac{1}{2} * (16+48)*x\\\\320 = \frac{1}{2}*64*x\\\\320=32x\\\\x=\frac{320}{32}\\\\x= 10\end{gathered}

320cm

2

=

2

1

∗(16+48)∗x

320=

2

1

∗64∗x

320=32x

x=

32

320

x=10