Question

Area of a Trapezium is 400m2 one of its parallel sides is 20m longer than the other and height is 10 M find its two parallel sides

Answer 1

h=10m
1st parallel side: x
2nd parallel side: x+20
area=400m square

area of trapezium: h/2 (a+b)
400=10/2(x+x+20)
400=5× (2x+20)
400=10x+100
400-100=10x
300=10x
30=x

1st parallel side: 30m
2nd parallel side: 30+20= 50m

Answer 2

The parallel sides are 30 m and 50 m

Step-by-step explanation:

Let the other side of trapezium be x

We are given that one of its parallel sides is 20m longer than the other

So, one of parallel sides = x+20

Height of trapezium = 10 m

Area of trapezium =$\frac{1}{2}(\text{Sum of parallel sides }) \times Height$

Area of trapezium =$\frac{1}{2}(20+x+x)10$

We are given that Area of a Trapezium is 400m2

So, $\frac{1}{2}(20+x+x)(10)= 400$

20+2x=80

2x=60

x=30

So, Parallel sides = x+20=30+30=50 m and 30 m

Hence The parallel sides are 30 m and 50 m

#Learn more:

The area of trapezium is 210cm²and its height is 5cm.if one the parallel side is longer than other by 8cm .find the two parallel sides

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