Question

Area of a trapezium is 720 cm². If the parallel sides are 8 cm and 12 cm long, What is the distance between parallel sides ?​

Answer 1

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Given:-

Area of trapezium=720cm²

Length of parallel sides= 8cm and 12 cm

Area=H×(Sum of length of parallel sides)

720=H×(8+12)

720=H×20

720/20=H

H=36

So height of given trapezium is 36 cm.

$\large{\color{aqua}{\underbrace {\underline{\color{red}{\mathbb{❥Hope\: it \:helps \:you....}}}}}}$

Answer 2

$\huge\purple{Required \: Answer :}$ .

Distance between parallel sides = 72 cm

$\huge\red{Explanation :}$

Given :

Area of Trapezium - $720 \: {cm}^{2}$

Parallel Sides - 8cm and 12cm

To Find :

Distance Between Parallel Sides (height) - ?

Formula :

$</u></em></strong><strong><em><u>A</u></em></strong><strong><em><u>rea = \frac{</u></em></strong><strong><em><u>S</u></em></strong><strong><em><u>um \: of \: </u></em></strong><strong><em><u>P</u></em></strong><strong><em><u>arallel \: </u></em></strong><strong><em><u>Si</u></em></strong><strong><em><u>des}{2} \times h$

Solution :

$720 \: {cm}^{2} = \frac{8 + 12}{2} \times h \\ 720 = \frac{20}{2} \times h \\ 720 = 10 \times h \\ h = \frac{720}{10} \\ h = 72 \: cm$

$\huge\bf{Thanks : ❤}$