Question

area of a trapezium pqrs p ,r = 25cm PQ = 17cm SR= 24cm ​

Answer 1

Answer:

Area of a trapezium ABCD

= area (∆DFA) + area (rectangle DFEC) + area (∆CEB)

= (¹/₂ × AF × DF) + (FE × DF) + (¹/₂ × EB × CE)

= (¹/₂ × AF × h) + (FE × h) + (¹/₂ × EB × h)

= ¹/₂ × h × (AF + 2FE + EB)

= ¹/₂ × h × (AF + FE + EB + FE)

= ¹/₂ × h × (AB + FE)

= ¹/₂ × h × (AB + DC) square units.

= ¹/₂ × (sum of parallel sides) × (distance between them)