Math, asked by devadath0077, 4 months ago

Area of a trapezium with parallel side 4cm and 11cm and perpendicular distance between them is 12cm

Answers

Answered by Anonymous
5

Answer:

90cm² is the area

Explanation:

Given

  • First parallel side = 4cm
  • Second parallel side = 11cm
  • Distance between the parallel sides = 12 cm

To Find

  • Area of the trapezium

Solution

The distance between the parallel sides is the height of the trapezium.

Area of a trapezium = 1/2 × height ( Sum of parallel sides )

Area = 1/2 × 12cm ( 4cm + 11cm )

Area = 6cm ( 4cm + 11cm )

Area = 6cm ( 15cm )

Area = 90 cm²

90cm² is the area

Answered by thebrainlykapil
15

Question :-

  • What is the Area of a trapezium with parallel side 4cm and 11cm and perpendicular distance between them is 12cm.

 \\  \\

Given :-

  • First Parallel Side = 4cm
  • Second Parallel Side = 11cm
  • Perpendicular distance between the parallel side ( height ) = 12cm

 \\  \\

To Find :-

  • Area of the Trapezium with given dimensions.

 \\  \\

Solution :-

 \\

 {:} \longrightarrow \sf \boxed{\bf{Area \: of \: Trapezium \: = \: \dfrac{1}{2}   \times Height \: \times ( Sum\: of\: parallel \:sides)  }}\\

 {:} \longrightarrow \sf {\sf{Area \: of \: Trapezium \: = \: \dfrac{1}{2}   \times\: 12 \: \times ( 4\: + \: 11)  }}\\

 {:} \longrightarrow \sf {\sf{Area \: of \: Trapezium \: = \: \dfrac{1}{2}   \times\: 12 \: \times15  }}\\

 {:} \longrightarrow \sf {\sf{Area \: of \: Trapezium \: = \: \dfrac{1}{ \cancel2}   \times\:  \cancel{12} \: \times15  }}\\

 {:} \longrightarrow \sf {\sf{Area \: of \: Trapezium \: = \: 6 \: \times15  }}\\

 {:} \longrightarrow \sf {\bf{Area \: of \: Trapezium \: = \: 90cm^{2}  }}\\

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\begin{gathered}\begin{gathered} \therefore\: \sf{Area \: of \: Trapezium \:  \: = \underline {\underline{ 90cm^{2}}}}\\\end{gathered}\end{gathered}

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More For Knowledge :-

  • Area of Square = Side x Side
  • Area of Rectangle = Length × Breadth
  • Area of Triangle = ½ × base x height
  • Area of parallelogram = base x height
  • Area of circle = πr²
  • Area of Rhombus = ½ × product of its diagonals
  • Area of Trapezium = ½ × height × sum of parallel sides
  • Area of Polygon = sum of the area of all regions into which it is divided

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