Question

area of a triangle having equal heights are 4:5 of smaller triangle is 8cm then base of larger triangle = _________

Answer 1

Given,

• Area of smaller triangle  = 4

• Area of larger triangle = 5

Let,

• Height of smaller triangle = h

• Height of larger triangle = H

• Base of smaller triangle = b

• Base of larger triangle = B

Here,

• Height of smaller triangle = Height of larger triangle = H

We know,

$\huge{\boxed{\sf{Area=\dfrac{1}{2} \times b \times h}}}$

$\sf{\implies \dfrac{{\dfrac{1}{2}\times H\times b}}{\dfrac{1}{2}\times H\times B}=\dfrac{4}{5}}$

$\sf{\implies \dfrac{8}{B}=\dfrac{4}{5}}$

$\sf{\implies B=\dfrac{8\times 5}{4}}$

$\sf{\implies B=\dfrac{40}{4}}$

$\sf{\implies B=10 \ cm}$

$\boxed{\sf{\therefore \ Base \ of \ larger \ triangle =10 \ cm}}$