Math, asked by sahumanoj0331, 7 months ago

area of a triangle having side2cm, 2cm, 2cm is​

Answers

Answered by Sahilvictor
1

Answer:

1/2*side

1/2*2=1

hope it helps you

Step-by-step explanation:

follow me please

Answered by Anonymous
2

\underline{\underline{\blue{\bf Answer:-}}}

\tt\therefore The:area\:of\: triangle\:is\:\sqrt3cm^2.

\underline{\underline{\orange{\bf Step-by-step\: Explanation:-}}}

\underline{\green{\bf Given:-}}

\tt:\implies Three\:sides\:of\: triangle\: are\:2cm,\:2cm\:,2cm .

\underline{\red{\bf To\:Find:-}}

\tt:\implies Area \:of\:the\: triangle.

\bf As\:we\:know\: that:-

\boxed{\pink{\bf \red{\bigstar}\:Area_{\triangle}=\sqrt{s(s-a)(s-b)(s-c)}}}

\tt:\implies Area =\sqrt{s(s-a)(s-b)(s-c)}\\\\\tt:\implies Area =\sqrt{ 3(3-2)(3-2)(3-2)} \\\\\tt:\implies Area = \sqrt{3\times1\times1\times1}\\\\\underline{\boxed{\red{\tt\longmapsto Area = \sqrt{3}cm^2}}}

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