Question

Area of a triangle having sides a, b and c is given by the following expression:
Area = s(s – a)(s - b)(s -c).
where s =a+b+c/2
Find the area of a triangle having sides 3, 4 and 5 units.​

Answer 1

Answer:

4✓2

Step-by-step explanation:

✓6(6-3)(6-4)(6-5)

✓32

=4✓2

Answer 2

Answer:

Question :

Area of a triangle having sides a, b and c is given by the following expression:

Area = s(s – a)(s - b)(s -c).

where s =a+b+c/2

Find the area of a triangle having sides 3, 4 and 5 units.

Answer :

$Area \: = \: \\ \sqrt{s(s - a)(s - b)(s - c)} {cm}^{2} \\ \\ Let \: us \: find \: s \\ \\ s \: = \frac{a + b + c}{2} \\ \\ = \frac{3 + 4 + 5}{2} \\ \\ = \frac{12}{2} \\ \\ = 6 \\ \\ s = 6 \\ \\ Area \: \\ \\ = \: \sqrt{6(6 - 3)(6 - 4)(6 - 5)} \\ \\ = \sqrt{6(3)(2)(1)} \\ \\ = \sqrt{6 \times 3 \times 2 \times 1} \: \\ \\ = \sqrt{6 \times 6} \\ \\ = 6 \\ \\ \\ \\ Area \: = 6 \: {cm}^{2}$

Therefore, the area of the triangle is 6 cm².

Thank you !