Question

area of a triangle whose perimeter is 180 cm and its two sides are 80 cm and 18cm calculate the altitude of the triangle corresponding to its shortest side

Answer 1

Perimeter of triangle:180cm
So,Third side
$= 180 - 80 - 18 = 82cm$
Since,s
$= 180 \div 2 = 90cm$
So,Area
$= \sqrt{90 \times (90 - 80) \times 90 - 18) \times 90 - 82}$
$\sqrt{90 \times 10 \times 72 \times 8}$

$= 10 \times 9 \times 8$
$= 720cm {}^{2}$
Now shortest side:18cm
Thus,
Area
$= 1 \div 2 \times b \times h$
$= 1 \div 2 \times 18 \times h$