area of a triangle with sides 3cm ,4cm , 5cm is
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Answered by
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Using the formulas
A=s(s﹣a)(s﹣b)(s﹣c)
s=a+b+c
2
Solving forA
A=1
4﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1
4·﹣34+2·(3·4)2+2·(3·5)2﹣44+2·(4·5)2﹣54=6cm²
A=s(s﹣a)(s﹣b)(s﹣c)
s=a+b+c
2
Solving forA
A=1
4﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1
4·﹣34+2·(3·4)2+2·(3·5)2﹣44+2·(4·5)2﹣54=6cm²
Anonymous:
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