Area of a triangle with vertices!
A (-4,3), B (2,8), el c (8,3) is
30, 42, 25, 40
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by distance formula,
a= √(2+4)^2 + (8-3)^2
=√61
b = √(8-2)^2+(3-8)^2
=√61
c = √(8+4)^2+(3-3)^2
= 12
s= semi- perimeter = (a+b+c)/2= √61+ 6
By Heron's formula,
Area = √s(s-a)(s-b)(s-c)
= √ [(√61+6) (√61+6-√61) (√61+6-√61) (√61+6-12)]
= 30
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