Question

Area of a triangle with vertices (k, 0), (1, 1) and (0, 3) is 5 unit. find the value (s) of k

Answer 1

Yrrr..its vey easy..just apply the area of triangle formula..u will get the answer

Answer 2

Answer:

The value of k is either -3.5 or 6.5.

Step-by-step explanation:

The vertices of triangle are (k, 0), (1, 1) and (0, 3).

The area of a triangle is

$A=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

The area of triangle is 5 sq units.

$5=\frac{1}{2}|k(1-3)+1(3-0)+(0)(0-1)|$

$10=|-2k+3|$

$10=\pm(-2k+3)$

$10=(-2k+3)$

$10-3=-2k$

$k=-3.5$

$10=-(-2k+3)$

$10=2k-3$

$13=2k$

$k=6.5$

Therefore the value of k is either -3.5 or 6.5.