Question

Area of ∆ABC is 360 sq.cm, Area ofquadrilateral BPGC is 110sq.cm - Ap=10cm,find AQ/QC
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Answer 1

Step-by-step explanation:

Observe that small and big triangles are similar

so area of similar triangles

$\frac{360}{360 - 110} = ( \frac{ab}{ap} )^{2} \\ \frac{ab}{ap} = \frac{6}{5}$

AP=10 , so AB=12.

PB=12-10=2

Now

$\frac{aq}{qc} = \frac{ap}{pb} = \frac{12}{2} = 6$