Area of ABCD is 36²cm find the area of triangle ABP
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Answer:
18 cm²
Step-by-step explanation:
Construction : Draw a perpendicular line to AB from P and name that as Q
a) Area of the rectangle ABCD = Length × Breadth = AB × CB = 36 cm²
AB × CB = 36 cm² ------ ( 1 )
Area of the ∆ABP = 1/2 × Base × Height
= 1/2 × AB × PQ
Since height of the triangle = Breadth of the rectangle, PQ = CB
= 1/2 × AB × CB
From eq( 1 )
= 36/2
= 18 cm²
Therefore the area of the ∆ ABP is 18 cm².
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