Question

area of adjacent figure is

Answer 1

area of rectangle+2×area of triangles=18×12+1/2×2×6×2=12×19=228

Answer 2

Answer:

252 sq.units

Step-by-step explanation:

Refer the attached figure

BC = FG = 12

BF = CG = 20

Area of rectangle FBCG = $Length \times Breadth$

                                        = $12 \times 20$

                                        = $240/tex]</p><p>Area of triangle = [tex]\frac{1}{2} \times Base \times Height$

Height of triangle AFE = 2

Base of triangle AFE = GF = $\frac{1}{2} GF= \frac{1}{2} \times 12 = 6$

Area of triangle AFE  = $\frac{1}{2} \times 6 \times 2$

                                   = 6

Height of triangle DEG = 2

Base of triangle DEG= GF = $\frac{1}{2} GF= \frac{1}{2} \times 12 = 6$

Area of triangle DEG  = $\frac{1}{2} \times 6 \times 2$

                                   = 6

So, total area of figure = 240+6+6 =252 sq.units