Question

Area of an equilateral triangle is 4 underoot 3 cmsq. What is its side?

Answer 1

Answer:

4 cm each

Given:

Area of equilateral triangle=4√3 cm^2

To find:

It's side

Solution:-

Let the sides be a

We know that

Area of equilateral triangle

$= \frac{ \sqrt{3} }{4} {a}^{2}$

Area is given 4√3

$4 \sqrt{3} = \frac{ \sqrt{3} }{4} {a}^{2}$

$4 = 4 {a}^{2}$

$16 = {a}^{2}$

$a = \sqrt{16}$

$a = 4 \: cm$

So all the sides of an equilateral triangle are equal i.e,4 cm

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★ Verification ★

$area = \frac{ \sqrt{3} }{4} {a}^{2}$

$= \frac{ \sqrt{3} }{4} \times 4 \times 4$

$4 \sqrt{3} \: {cm}^{2}$

Answer 2

Answer :-

Given :-

Area of equilateral Triangle = 4√3cm²

To Find :-

Side of the rectangle

Solution :-

We know that area of triangle is √3/4 a²

$\frac{ \sqrt{3} }{4} {a}^{2} = \: 4 \sqrt{3} \\ \\ 4 {a}^{2} = 4 \\ \\ 16 = {a}^{2} \\ \\ \sqrt{16} = a \\ \\ a = 14$

Hence ,the side of triangle is 4cm.