Question

area of an isosceles right angle triangle is 8sq. m. find its hypotenuse

Answer 1

Hey there! ☺☻☺

Given,
Let two equal sides be x.
Area of triangle = 8 m²
1/2 * base * height = 8
1/2 * x*x = 8
x² = 16
x = 4

Now, two base and height =  4 cm
We know,
Pythagoras theorem,
H² = B² + P²
H² = 4² + 4²
H² = 32
H = √32
H = 4√2

Hope It Helps You! ☺☻☺

Answer 2

Hey!


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Isosceles triangle is a triangle whose two sides are equal, hypotenuse is always greater than other side's, thus height and base is equal.

Area of the triangle = 8 m^2
Let the side be x
Base = x
Height = x

Area = 1/2 × b × h
8 = 1/2 × x × x
8 = 1/2 × x^2
8×2 = x^2
16 = x^2
x = √16
x= 4 m

Hypotenuse^2 = B^2 + P^2
H^2 = 4^2 + 4^2
H^2 = 16 + 16
H^2 = 32
H = √32
H = 4√2 m

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Hope it helps...!!!