Question

area of an isosceles triangle is 48 cm^ if the altitudes corresponding to the base of the triangle is 8 m find the perimeter of the triangle

Answer 1

let ABC be the isosceles triangle, the AD be the altitude

Let AB = AC = x then BC= 32-2x [because parameter = 2 (side) + Base]

since in an isoceles triange the altitude bisects the base so

BD = DC = 16-x

In a triangle ADC, (AC)2=(AD)2+(DC)2

x2=82+(16−x)2 ⇒x=10

BC = 32-2x = 32-20 = 12 cm

Hence, required area = 12*BC*AD= 12*12*10 = 60 sq cm

I hope it will help you