Question

Area of an isosceles triangle is 48cm. If the altitudes corresponding to the base of the triangle is 8 cm, find the perimeter of the triangle.​

Answer 1

Answer:

P ≈ 33.3cm

Step-by-step explanation:

Given, Area of triangle ABC=48sq.cm  

Height AD=8cm  

Area of triangle ABC,

⇒48=  

2

1

​  

×BC×AD=  

2

1

​  

×BC×8

⇒BC=  

8

48×2

​  

=12cm

Now, in an isosceles triangle height is also median, so D is midpoint of BC  

⇒BD=DC=6cm  

By, Pythagoras theorem in triangle ADB.

⇒AB  

2

=BD  

2

+AD  

2

 

⇒AB  

2

=6  

2

+8  

2

 

⇒AB  

2

=36+64=100

⇒AB=10cm

∴AC=AB=10 cm

Now, perimeter of triangle =AB+AC+BC

=10+10+12

=32cm

Answer 2

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