area of an isosceles triangle is 48sq.cm.if the altitudes corresponding to the base of the triangle is 8cm,find the perimeter of the triangle
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Answered by
0
Answer:
area=48sq.cm
hight=8cm
base=area*2/h
=48*2/8=12 cm
perimeter =8+12+12=32cm
Answered by
0
Answer:
12cm
Step-by-step explanation:
Base = b
Altitude = 8cm
Area = 48sqcm
Area of triangle = 1/2*b*h
48 = 1/2*b*8
48/8 = 1/2*b
6 = 1/2*b
6*2/1 = b
12 = b
Perimeter = base+altitude+altitude
= 12+8+8
= 12+16
= 28cm
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