Question

area of an isosceles triangle whose base is a and equal sides b​

Answer 1

Step-by-step explanation:

given : we have isosceles triangle with sides a b and b

we know Heron's formula :

area of triangle =a(s-a) (s-b) (s-c)---------√

Here

a,b and c are sides of triangle

and

s =a+b+c2

here

a=a , b=b and c=b, so ,

s=a+b+b2=a+2b2

and

area of given isosceles triangle :

a+2b2(a+2b2-a)(a+2b2-b)

(a+2b2-b)

a+2b2(a+2b-2a2)

(a+2b-2b2)(a+2b-2b2)

a+2b2(b-a2)(a2)(a2)

√ (a+2b)(b-a)(a2)16

√ a(a+2b)

(b-a)√4= a(ab-a2+2b2-2ab)√4=

a2b2-a2-ab√4

( Ans.)

I hope this is your help full