Area of an isoscles triangle XYŹ in which XY=YZ=6cm and YZ=10cm
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As we know the property of isoscles triangle, if we draw a perpendicular in the isocles triangle then it divides the base into two equal parts then by Pythagoras theorem,
we can find its height
perpendicular squr. = hypotenuse square. - base squr.
p^2= h^2-b^2
p^2= 6^2-5^2
p= √11
so height is √11
so area,
1/2×10×√11
5√11cm ^2
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