Question

Area of arectangle 820 sq.Cm width 20 cm what is length find its perimeter

Answer 1

Answer:

Step-by-step explanation:

Area of rect. =l×b

Breadth=20cm

Area=820sq.cm

.: 820=20×l

L=820/20

L=41cm

Perimeter =2(l+b)

" " " =2(41+20)

=2(61)

=122 cm