Question

area of base of a cylinder is 400 cm^2. water is poured upto depth 0,8m. calculate the pressure and thrust of water at the base in SI unit.
(Density of water is 1g/cm^3)
formula's
pressure = depth x density x acceleration due to gravity
thrust = pressure / area​

Answer 1

Answer:

We begin by solving the equation P = hρg for depth h: h=Pρg h = P ρ g . Then we take P to be 1.00 atm and ρ to be the density of the water that creates the pressure.