Question

Area of cross section of X is 0.05 square meter and that of Y is 1 square metre . If a force of 200 N is acting on X what will be the force experienced on Y​

Answer 1

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${f}^{1} = \: {120}^{n} \\ {a}^{1} = {0.05m}^{2} \\ {a}^{2} = {0.6m}^{2} \\ {f}^{2} = \\ {f}^{2} = ( \frac{ {a}^{2} }{ {a}^{1} } ) {f}^{1} \\ {f}^{2} = ( \frac{0.6}{0.05} )120 \\ {f}^{2} = 1440n$

Answer 2

Answer:

Area of cross section of X is 0.05 square meter and that of Y is 1 square metre . If a force of 200 N is acting on X what will be the force experienced on Y