Question

Area of design =? cbse 2014, 17​

Answer 1

Answer:

Step-by-step explanation:

AB = BC = CD = AD = 8 cm

Area of ΔABC = Area of ΔADC = 1/2 × 8 × 8 = 32 cm2

Area of quadrant AECB = Area of quadrant AFCD = 1/4 × 22/7 × 82

                                                    = 352/7 cm2

Area of shaded region = (Area of quadrant AECB - Area of ΔABC) +                                           (Area of quadrant AFCD - Area of ΔADC)

                                   = (352/7 - 32) + (352/7 -32) cm2

                                               = 2 × (352/7 -32) cm2

                                                =  256/7 cm2