Area of equilateral triangle is 24 root of 3, then perimeter is ?
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FIRST OF ALL AREA = ROOT 3 / 4 × SIDES^2
PERIMETER = 3 × SIDES
(SIDES = A)
SO UR ANSWER IS
=> AREA = ROOT 3 / 4 × A^2
=> 24 ROOT 3 = ROOT 3 / 4 × A^2
=> A^2 = 24 ROOT 3 × 4 / ROOT 3
=> A^2 = 24 × 4
=> A^2 = 96
=> A = 4 ROOT 6
PERIMETER = 3 × A
= 3 × 4 ROOT 6
= 12 ROOT 6
SO UR ANSWER IS
PERIMETER = 12 ROOT 6
HOPE IT HELPS U PLZ MARK ME AS A BRAINLIST PLZ
PERIMETER = 3 × SIDES
(SIDES = A)
SO UR ANSWER IS
=> AREA = ROOT 3 / 4 × A^2
=> 24 ROOT 3 = ROOT 3 / 4 × A^2
=> A^2 = 24 ROOT 3 × 4 / ROOT 3
=> A^2 = 24 × 4
=> A^2 = 96
=> A = 4 ROOT 6
PERIMETER = 3 × A
= 3 × 4 ROOT 6
= 12 ROOT 6
SO UR ANSWER IS
PERIMETER = 12 ROOT 6
HOPE IT HELPS U PLZ MARK ME AS A BRAINLIST PLZ
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