Question

area of equilateta triangle is 2√3cm sq find its semi perimeter

Answer 1

the semiperimeter is [2*2^(1/2)]*3

Answer 2

$area = 2 \sqrt{3} \\ \frac{ \sqrt{3} }{4} \times {a}^{2} = 2 \sqrt{3} \\ {a }^{2} = \frac{2 \sqrt{3} \times 4 }{ \sqrt{3} } \\ {a}^{2} = 8 \\ a = 2 \sqrt{2} \\ semi \: perimeter = \frac{3 \times 2 \sqrt{2} }{2} \\ = 3 \sqrt{2}$