Area of four walls of a room is a) 2(length + Breadth) b) 2× height × ( length + Breadth ) c) 2× length × Breadth
Answers
Answered by
1
Answer:
It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.
Area of four walls of the room is: 2h(l+b)
A=2h(l+b)=2×3(8+5)=6×13=78 m
2
Area of the ceiling is:
A=l×b=8×5=40 m
2
Total area of the four walls and the ceiling of the room is 78+40=118 m
2
It is given that cost of white washing is Rs.15/m
2
, therefore,
Total cost of white washing is:
118×15=1770
Hence, the cost of white washing the walls is Rs.1770.
Step-by-step explanation:
hope it helps
Similar questions