Area of four walls of a room of dimensions 25m,35m,40m is
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Answered by
6
Answer:
It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.
Area of four walls of the room is: 2h(l+b)
A=2h(l+b)=2×3(8+5)=6×13=78 m2
Area of the ceiling is:
A=l×b=8×5=40 m2
Total area of the four walls and the ceiling of the room is 78+40=118 m2
It is given that cost of white washing is Rs.15/m2, therefore,
Total cost of white washing is:
118×15=1770
Hence, the cost of white washing the walls is Rs.1770.
Answered by
2
Answer:
Total surface area of cuboid = 2 (lb + bh + hl)
2(40×35 + 35×25 + 25×40)
= 2(1400 + 875 + 1000)
= 6550m²
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