Area of hexagon inscribed in a circle formula
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In an regular hexagon inscribed in a circle, its side is equal the radius.
We can divide the hexagon in 6 triangles each with the base of 4. The heigth will equal 42−22−−−−−−√=12−−√=23√42−22=12=23. To obtain this just use Pythagoras, the hypotenuse of each triangle it's the radius, and the bases it's 42=242=2.
Now you have the height of each triangle, so At=(4∗23√)/2=43√At=(4∗23)/2=43.
Ah=6∗At=6∗43√=243√
We can divide the hexagon in 6 triangles each with the base of 4. The heigth will equal 42−22−−−−−−√=12−−√=23√42−22=12=23. To obtain this just use Pythagoras, the hypotenuse of each triangle it's the radius, and the bases it's 42=242=2.
Now you have the height of each triangle, so At=(4∗23√)/2=43√At=(4∗23)/2=43.
Ah=6∗At=6∗43√=243√
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