area of house is in the shape of a trapezium with parallel side in the ratio 3 ratio 5 its area is 50 m square that the perpendicular distance between the parallel side is 5 metres.find the length of two parallel side of that open area
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Answered by
45
Given that
area = 50 m²
Perpendicular distance (height) = 5 m
Ratio of parallel sides = 3 : 5
Let the parallel sides be 3x and 5x
Now we know that the area of a trapezium is
1/2 × (sum of parallel sides) × height = area
Here, putting the values we get
=> 1/2 × (3x + 5x) × 5 = 50
=> 5/2 × (8x) = 50
=> 8x = 50 × 2/5
=> 8x = 20
=> x = 20/8
=> x = 5/2
Now first side = 3x
=> 3 × 5/2
= 15/2 metres
= 7.5 metres
Second side = 5x = 5 × 5/2
= 25/2 metres
= 12.5 metres
Hope it helps dear friend ☺️
area = 50 m²
Perpendicular distance (height) = 5 m
Ratio of parallel sides = 3 : 5
Let the parallel sides be 3x and 5x
Now we know that the area of a trapezium is
1/2 × (sum of parallel sides) × height = area
Here, putting the values we get
=> 1/2 × (3x + 5x) × 5 = 50
=> 5/2 × (8x) = 50
=> 8x = 50 × 2/5
=> 8x = 20
=> x = 20/8
=> x = 5/2
Now first side = 3x
=> 3 × 5/2
= 15/2 metres
= 7.5 metres
Second side = 5x = 5 × 5/2
= 25/2 metres
= 12.5 metres
Hope it helps dear friend ☺️
SillySam:
✌✌✌ Keep it up..❤☺☺
Answered by
19
Let the parallel sides be 3x and 5x.
Area of trapezium = 1/2*(sum of parallel sides)*height
50 = 1/2*(3x+5x)*5
8x=20
x=2.5 m
Length of parallel sides = 3*2.5 = 7.5 m, 5*2.5 = 12.5 m
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