Question

area,of iscoceles right triangle is 8 cm². Find its hypotenus side.​

Answer 1

Answer:

Both the perpendicular and base are equal in length.

So Area of triangle = 1/2 x b x h

Let b = h = y

1/2 x y x y = 8

y² = 16

y = 4

So Perpendicular = Base = 4 cm

Now by Pythagoras theorem,

4² + 4² = √ 16+ 16 = √32 = 4√2 cm

So required hypotenuse = 4√2 cm

Answer 2

Answer:

$x = 32$

Step-by-step explanation:

$area \: of \: triangle \: = 8cm {}^{2}$

$let \: the \: other \: \: side \: \: be \: x$

A/Q

$h = 8cm {}^{2} = x + x$

$8cm {}^{2} = 2x$

$x = 64cm \div 2$

$x = 32$

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