Question

Area of isosceles triangle is 338 cm² and its base is 13 cm find height ?

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Answer 1

Height of the triangle is 52 cm.

Step-by-step explanation:

An isosceles triangle has both two equal sides and two equal angles.

Given:

Area= 338 $cm^{2}$ and base = 13 cm and the triangle is an isosceles triangle.

Formula:

Area of a triangle is given by:

$area = \frac{1}{2} X base X height$

Let the height be h.

$338 = \frac{1}{2} X 13 X h\\\\h=\frac{2X338}{13}\\\\h=52 cm$

So, height of the triangle is 52 cm.

Answer 2

Answer:

The height of the triangle is $52cm$

Step-by-step explanation:

Given:

The area of isosceles triangle is $338cm^2$

The base is $13cm$

we need to find the height

As we know the area of a triangle is $A=\frac{1}{2} *b*h$

By substituting we get

$338=\frac{1}{2} *13*h\\\\h=\frac{338*2}{13} \\\\h=52$