Question

area of isosceles triangle whose equal sides measure 5 cm each and height corresponding to the third side is 4 cm

Answer 1

$We\ have\ measures\ of\ equal\ sides\ and\ height \\ corresponding\ to\ third\ side. \\ \\ As\ it\ is\ isosceles,\ when\ we\ subtract\ the\ square\ of\ height \\ from\ the\ square\ of\ one\ among\ equal\ sides,\ we\ get\ square\ of \\ half\ of\ the\ third\ side. \\ \\ \therefore\ Third\ side \\ \\ = 2\sqrt{(5^2 - 4^2)} \\ \\ = 2\sqrt{(25 - 16)} \\ \\ = 2\sqrt{9} \\ \\ = 2 \times 3 = 6\ cm$

$\\ \\ \\ Let's\ find\ the\ area. \\ \\ \\ Area \\ \\ = \frac{1}{2} \times 6 \times 4 \\ \\ = \frac{1}{2} \times 24 = 12\ cm^2$

$\\ \\ \\ Thank\ you. \\ \\ \\ \#adithyasajeevan$

Answer 2

Answer:

inderpreet kaur mnaan