area of isosceles triangle whose side are 12cm each and the perimeter is 30cm.
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Answered by
1
Let the third side of this triangle be x.Perimeter of triangle = 30 cm12 cm + 12 cm + x = 30 cmx = 6 cm
s= perimeter of the triangle /2 = 30/2 = 15cm
by Herons formula,
area of the triangle = (root of) s(s-a)(s-b)(s-c)
= (root of) 15 x (15-12) (15-12) (15-6)
= (root of) 15 x 3 x 3 x 9
= (root of) 3 x 5 x 3 x 3 x 3 x 3
= 3 x 3 (root of) 5 x 3
= 9 (root of) 15 cm^3
s= perimeter of the triangle /2 = 30/2 = 15cm
by Herons formula,
area of the triangle = (root of) s(s-a)(s-b)(s-c)
= (root of) 15 x (15-12) (15-12) (15-6)
= (root of) 15 x 3 x 3 x 9
= (root of) 3 x 5 x 3 x 3 x 3 x 3
= 3 x 3 (root of) 5 x 3
= 9 (root of) 15 cm^3
Answered by
1
there r three sides
so, sides r =12cm,9cm,9cm
area=18root5 cm^2
by herons formula
so, sides r =12cm,9cm,9cm
area=18root5 cm^2
by herons formula
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