area of issoscale triangle formula
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Area of isoceles triange is
A=bh/2
b= base
h=height
A=bh/2
b= base
h=height
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Isosceles triangle has two equal and an unequal side.
Let ΔABC∆ABC be an isosceles triangle with sides AB=AC=aAB=AC=a and BC=bBC=b. Let the altitude be drawn from A to BC. Then altitude AD=hAD=h
Then, area of ΔABC,S=b∗h2∆ABC,S=b∗h2
But we don't have value for hh. The altitude AD will be at 90° with BC. Hence it will form 2 right triangles. Then in ΔABD,AD2=AB2−(BC2)2∆ABD,AD2=AB2−(BC2)2
h2=a2−b24h2=a2−b24
h=4a2−b2√2h=4a2−b22
Then, area of ΔABC,S=b∗h2=b2∗4a2−b2√2=b4∗4a2−b2−−−−−−−√=b4∗(2a+b)(2a−b)−−−−−−−−−−−−−√
an eg. is posted above
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