Area of largest isosceles triangle inscribed in a circle
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As said in the title, I'm looking for the maximum area of a isosceles triangle in a circle with a radius r.
I've split the isosceles triangle in two, and I solve for the area A=bh2*. I have made my base x, and solve for the height by using the Pythagorean theorem of the smaller triangle (seen in picture).
h=r+√r2−x2
I've split the isosceles triangle in two, and I solve for the area A=bh2*. I have made my base x, and solve for the height by using the Pythagorean theorem of the smaller triangle (seen in picture).
h=r+√r2−x2
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