Area of liquid film is 6*10 and surface tension is t= 20 what is the work
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Answer:
Initial Area = 6 × 10 cm²
Final Area = 12 × 10 cm²
Surface Tension (T or S) = 20 dyne/cm.
Now, Using the Formula,
Work done = Change in area × Surface Tension
∴ Work done = (120 - 60) × 20
∴ Work done = 60 × 20
⇒ Work done = 1200 erg.
Since, the film is considered as double layered, therefore, Total work done = 2 × 1200 erg.
= 2400 erg.
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