Question

Area of minor sector of a circle is 3.85sq.cm and the measure of its central angle is 36° find its radius

Answer 1

area of sector =
$\frac{central \: angle}{360} \times \pi {r}^{2}$
area of sector = 3.85 cm²
Central angle = 36°

putting the values given in the question in the above equation.
$3.85 = \frac{36}{360} \times \frac{22}{7} \times {r}^{2} \\ 3.85 = \frac{1}{10} \times \frac{22}{7} \times {r}^{2} \\ 3.85 = \frac{22}{70} \times {r}^{2} \\ {r}^{2} = 3.85 \times \frac{70}{22} \\ {r}^{2} = 12.25 \\ r = \sqrt{12.25} \\ r = 3.5$
radius of circle = 3.5 CM

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Answer 2

Answer:

I hope its help

Step-by-step explanation:

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