Question

area of parallelogram abcd is 268 sq cm if its one diagonal ac 12 cm than measure diagonal bd

Answer 1

Answer:

44.6 cm

Step-by-step explanation:

Given area of parallelogram abcd is 268 sq cm if its one diagonal ac 12 cm than measure diagonal bd

Let ABCD be a parallelogram in which AC and BD are diagonals intersecting at point O

The parallelogram is divided into two triangles ADC and ABC

Area of triangles Δ ADC + ΔABC = 268 cm square

We know that area of triangle = 1/2 base x height

 1/2 x AC x DO + 1/2 x AC x OB

1/2 x 12 x DO + 1/2 x 12 x OB

  6 DO + 6 OB = 268

 6 (DO + OB) = 268

 6 BD = 268

   BD = 268 /6

BD = 44.6 cm