Question

area of parallelogram formed by lines x+y+1=0, x+y+3=0,3x+4y-1=0 and 3x+4y-5=0

Answer 1

Answer:

Given equations of lines are

3x−4y+1=0,3x−4y+3=0,4x−3y−1=0 and 4x−3y−2=0,

Here m

1

=

4

3

,m

2

=

3

4

and c

1

=

4

1

,c

2

=

4

3

,d

1

=−

3

1

,d

2

=−

3

2

Area of parallelogram =

∣

∣

∣

∣

∣

m

1

−m

2

(c

1

−c

2

)(d

1

−d

2

)

∣

∣

∣

∣

∣

=

7

2

sq.units