Math, asked by snehalkhedekar04, 3 months ago

area of parallelogram is 400cm^(2) and it height is 16cm find its base ​

Answers

Answered by llNidhill
12

Given:

  • Area Of parallelogram = 400cm²
  • Height of parallelogram = 16cm

To find:

  • Find the Base

Solution:

 \sf      \green\bigstar\green{Area \: of \: Paralellogram  = Base \times Height }\ \  \\  \tt \color{lime}{400 = b \times 16} \\ \sf \color{lightgreen} b =  \frac{400}{16}  \\   \tt \color{green}  = \frac{ \cancel{400} \tiny25}{ \cancel{16} \tiny1 }  \\   \sf \color{orange} \underline{ = 25} \\  \tt   \pink{Hence, \: Base = 25}

Know More:

  • Area of Square = s²
  • Area of rectangle = l×b
  • Area of Triangle= 1/2×b×h
  • Area of Circle = πr²

Answered by Anonymous
16

Given that, area of parallelogram is 400cm² and its height is 16cm.

__________________________________

To Find:

➺it's base,

Analysis:

as, per the given measurements we have to find the base of the parallelogram.

here we use the formula:

 { \pink\mapsto \tt \: area \: of \: a \: parallelogram = base \times height}

Solution:

➷let's find it.!

: \implies \sf \: area = base \times height \\  \\  \\ : \implies \sf \:400 =  b \times 16 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\ : \implies \sf \:base =  \cancel \frac{400}{16}   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\ : \implies \bf \: base = 25cm  \bigstar\:  \:  \:  \:  \:  \:

\blue{ \underline{ \boxed{ \pink{ \mathfrak{ \therefore \: base \: of \: the \: figure = 25cm}}}}}

Do you know.?

\leadsto \rm area \: of \: a \: triangle =  \frac{1}{2}  \times b \times h \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \leadsto \rm area \: of \: a \: rectangle = lenght \times width \\  \\ \leadsto \rm area \: of \: a \: square =  {side}^{2}   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \\  \\\leadsto \rm area \: of \: a \: rhombus =  \frac{d1 \times d2}{2}    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \\  \\ \leadsto \rm area \: of \: a \: trapiezium =  \frac{a + b}{2}  \times h \:  \:  \:  \:  \:

hope this helps.!

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