area of parallelogram is 432 cm^2.If BC||AD and the distance between BC and AD is 20 cm, what is the measure of the side BC of parallelogramABCD.
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area of parallelogram = base * height
= BC * AD
= BC * 20
so BC * 20 = 432
BC = 432/20 = 21.6
= BC * AD
= BC * 20
so BC * 20 = 432
BC = 432/20 = 21.6
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