Question

Area of parallelogram is p cm^2 and its height is q cm. A second parallelogram has equal area but its base is r cm more than that of the first.

Answer 1

This is your answer

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Answer 2

Step-by-step explanation:

Solution :

Area of 1st parallelogram = p cm²

b × h = p

b × q = p

b = p/q cm

Base = (r + p/q)

= rq + p/q

Area of 2nd parallelogram = p cm²

b × h = p

rq + p/q × h = p

h = pq/rq + p cm.