Area of Part 1: No. of whole souares = 3 boxes = 3 souare unit
No. of souare more than half boxes = 1 square unit (we considers
al)
No of swuare less than half = 2 boxes: O souare unit we consider as a 0)
So, area of part 1 = 3square unit + 1 square unit = 4 square unit
Note-Now observe the above solution and find the area of part 2,3,4,5,6
0.2 Find the area and perimeter of each part
PARTS
PERIMITER
Head
Body
One Arm
One Leg
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Step-by-step explanation:
If we see the given figure, we find,
Number of fully-filled square =11
Number of half-filled square =3
Number of more than half-filled square =7
Number of less than half-filled square =1
If we consider the area of each square is 1 square unit and more than half-filled has 1 sq unit area,
Area of fully-filled square =11∗1=11 square unit
Area of more than half-filled square =7∗1=7 square unit
Now, if the area of each half-filled square is 12 square unit and less than half-filled has 0 sq unit area,
Area of half-filled square =3∗12=32 square unit
Area of less than half-filled square =5∗0=0 square unit
So, total area =11+7+32+0=19.5 square units
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