Question

area of quadrilateral ABCD
is 36 CM square B is the midpoint of AC find the area of triangle ABC if ab is parallel to de and B parallel to DC​

Answer 1

Answer:

Given, ABCD is a parallelogram having P as mid point of AB.

Join the diagonal AC and PC.

We know that the diagonal of a parallelogram divides it into two triangles of equal area.

Therefore, Ar (ABC) = Ar (ADC) = x cm

2

(let)

Also, let area of APC = BPC = y cm

2

(let) [Again, the median of a triangle divides a triangle into two triangles of equal area]

Given, Ar(APCD) = 36 cm

2

⟹Ar(ACD)+Ar(APC)=36

⟹x+y=36...(1)

Again, Ar (ABC) = Ar (ADC)

or, Ar (ABC) = Ar (APC) + Ar (BPC)

or, x = y + y

or, x = 2y .... (2)

Putting value of x in (1), we get

2y+y=36

⟹y=12cm

2

Therefore, x = 24 cm

2

Hence, Ar(ABC) = 24 cm

2

ANSWER IS 24 cm^2

Step-by-step explanation:

HOPE IT HELPS.....