Question

area of quadrilateral of d=8 h1=4 b=5​

Answer 1

Answer:

66 cm²

Step-by-step explanation:

Area of quadrilateral ABCD=

2

1

d(h

1

+h

2

)

Sum of the length of perpendicular from the remaining two vertices on the diagonal AC=(h

1

+h

2

)

h

1

+h

2

=12cm.

Length of the diagonal (BD)=11cm.

∴ Area of quadrilateral =

2

1

d(h

1

+h

2

)=

2

1

×12×11=6×11=66 cm

2

.