Question

Area of quadrilateral whose vertices are A(0,-4), B (4,0), C (-4,0), D (0,4)
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Answer 1

Answer:

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Answer 2

Answer:

Area of quadrilateral ABCD = Area of triangle ABC + Area of triangle ADC

Area of triangle =

2

1

×[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

3

−y

1

)]

Area of△ABC=

2

1

[2(3−2)+2(2−1)+(−2)(1−3)]=

2

1

×8=4sq.units

Area of△ADC=

2

1

[2(0−2)+(−1)(2−1)+(−2)(−1−2)]=

2

1

×1=

2

1

sq.units

Area of quadrilateral ABCD=4+

2

1

=

2

9

sq.units

solution